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(F)=5F^2+6F-12
We move all terms to the left:
(F)-(5F^2+6F-12)=0
We get rid of parentheses
-5F^2+F-6F+12=0
We add all the numbers together, and all the variables
-5F^2-5F+12=0
a = -5; b = -5; c = +12;
Δ = b2-4ac
Δ = -52-4·(-5)·12
Δ = 265
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$F_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$F_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$F_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-5)-\sqrt{265}}{2*-5}=\frac{5-\sqrt{265}}{-10} $$F_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-5)+\sqrt{265}}{2*-5}=\frac{5+\sqrt{265}}{-10} $
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